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		<title>Video: Interviews about Education (Somerville)</title>
		<link>http://iceaccis.wordpress.com/2010/05/27/video-interviews-about-education-somerville/</link>
		<comments>http://iceaccis.wordpress.com/2010/05/27/video-interviews-about-education-somerville/#comments</comments>
		<pubDate>Thu, 27 May 2010 20:46:39 +0000</pubDate>
		<dc:creator>iceaccis</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

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			<content:encoded><![CDATA[<div class='embed-vimeo' style='text-align:center;'><iframe src='http://player.vimeo.com/video/12083653' width='400' height='300' frameborder='0'></iframe></div>
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		<title>Counting with Golf Balls</title>
		<link>http://iceaccis.wordpress.com/2010/05/26/counting/</link>
		<comments>http://iceaccis.wordpress.com/2010/05/26/counting/#comments</comments>
		<pubDate>Wed, 26 May 2010 17:26:43 +0000</pubDate>
		<dc:creator>iceaccis</dc:creator>
				<category><![CDATA[Triangles]]></category>

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		<description><![CDATA[I realized I could find out how many golf balls there are in a triangle by (1) adding 1 to the number of rows, (2) multiplying this by the number of balls in the base, and (3) dividing the result &#8230; <a href="http://iceaccis.wordpress.com/2010/05/26/counting/">Continue reading <span class="meta-nav">&#8594;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=iceaccis.wordpress.com&amp;blog=13858342&amp;post=70&amp;subd=iceaccis&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<div id="attachment_83" class="wp-caption alignnone" style="width: 510px"><a href="http://iceaccis.files.wordpress.com/2010/05/golf-balls.jpg"><img class="size-full wp-image-83" title="golf-balls" src="http://iceaccis.files.wordpress.com/2010/05/golf-balls.jpg?w=640" alt="Golf balls in a triangle"   /></a><p class="wp-caption-text">golf balls arranged on my basement floor</p></div>
<p>I realized I could find out how many golf balls there are in a triangle by <span style="color:#888888;">(1)</span> adding 1 to the number of rows, <span style="color:#888888;">(2)</span> multiplying this by the number of balls in the base, and <span style="color:#888888;">(3)</span> dividing the result by 2.</p>
<p>What I&#8217;m actually doing here is just adding all of the numbers from 1 to 16.</p>
<h2><strong><span style="color:#444444;">Visual proof</span></strong></h2>
<p>from <a href="http://www.billthelizard.com/2009/07/six-visual-proofs_25.html">Bill the Lizard&#8217;s blog</a>:</p>
<div id="attachment_86" class="wp-caption alignnone" style="width: 314px"><a href="http://iceaccis.files.wordpress.com/2010/05/sum.png"><img class="size-full wp-image-86" title="sum" src="http://iceaccis.files.wordpress.com/2010/05/sum.png?w=640" alt=""   /></a><p class="wp-caption-text">1 + 2 + 3 + ... + n = n * (n+1) / 2</p></div>
<p>When I asked Bill for an explanation, here&#8217;s what he said:</p>
<blockquote><p>Hi Josh, thanks for commenting. There&#8217;s an old story about Gauss that might shed some light on the fourth proof. (I&#8217;m quoting from <a rel="nofollow" href="http://www.billthelizard.com/2009/01/gauss.html">my own post about Gauss</a>, but this story has been retold hundreds of times.)</p>
<p>&#8220;When Gauss was in school at age 10, his teacher, perhaps needing a quiet half hour, gave his class the problem of adding all the integers from 1 to 100. Gauss immediately wrote down the answer on his slate (this would have been in the year 1787). He had quickly noticed that the sum (1 + 2 + 3 + &#8230; + 100) could be rearranged to form the pairs (1 + 100) + (2 + 99) + (3 + 98) + &#8230; + (50 + 51), and that there were 50 pairs each equaling 101. This reduced the problem to the simple product 50 x 101 = 5050.&#8221;</p>
<p>The fourth proof here is illustrating the same idea. It&#8217;s just arranging the numbers in a different way than Gauss did over 200 years ago.</p>
<p>I hope that helps.</p></blockquote>
<p>Pretty cool, huh?</p>
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